2c^2+13c=7

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Solution for 2c^2+13c=7 equation:


Simplifying
2c2 + 13c = 7

Reorder the terms:
13c + 2c2 = 7

Solving
13c + 2c2 = 7

Solving for variable 'c'.

Reorder the terms:
-7 + 13c + 2c2 = 7 + -7

Combine like terms: 7 + -7 = 0
-7 + 13c + 2c2 = 0

Factor a trinomial.
(-7 + -1c)(1 + -2c) = 0

Subproblem 1

Set the factor '(-7 + -1c)' equal to zero and attempt to solve: Simplifying -7 + -1c = 0 Solving -7 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1c = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1c = 0 + 7 -1c = 0 + 7 Combine like terms: 0 + 7 = 7 -1c = 7 Divide each side by '-1'. c = -7 Simplifying c = -7

Subproblem 2

Set the factor '(1 + -2c)' equal to zero and attempt to solve: Simplifying 1 + -2c = 0 Solving 1 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2c = 0 + -1 -2c = 0 + -1 Combine like terms: 0 + -1 = -1 -2c = -1 Divide each side by '-2'. c = 0.5 Simplifying c = 0.5

Solution

c = {-7, 0.5}

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